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FindDuplicateCharacters ( string )

Returns True if the given string

  Average rating: 5.0 (1 vote) Log in to vote

RealGrouchy - Show more from this author http://twitter.com/RealGrouchy

  Function definition: (Copy & paste into FileMaker's Edit Custom Function window)

// FindDuplicateCharacters // 2018-06-08 // If the given string has the same character more than once, repeat True, otherwise False Let ( [ thisChar = Left ( string ; 1 ) ; otherChars = Right ( string ; Length ( string ) - 1 ) ] ; Case ( /* Return 1 if the first character is found elsewhere in the string (not returning the character because the character might be 0 which could be interpreted as false) */ PatternCount ( otherChars ; thisChar ) ; 1 ; /* If the function has run through all characters without finding a duplicate, return False */ Length ( otherChars ) <= 1 ; False ; /* Otherwise recur with the remaining part of the string */ FindDuplicateCharacters ( otherChars ) ) // Case ) // Let Click to copy

There are plenty of functions out there to find and manipulate unique or duplicate values within a given list of ¶ delimited values, but I couldn't find anything that looked for duplicate *characters* within a string. I whipped this one up.

It's simple enough but I figured I'll upload it for the next person who goes looking for it. It took me more time to look for it than to recreate it because I assumed there *must* be one out there! There probably is one and I just didn't use the right search terms.

- RG>

 

Comments

		esc, tokyo Jun 11, 2018
=1 would be better if <=1 now this function get into infinite loop if parameter is shorter than 1 character (then get ? as result).

		RealGrouchy Jun 11, 2018
Good catch. I've submitted the change! - RG>

		Tom Hays, Virgina, USA Aug 17, 2018
If the characters in the string are limited to a specific range/set of characters that you can specify explicitly, e.g. 0-9a-zA-Z, then you can write this in a closed form without needing recursion. Let([ alphanum = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ" ]; Length(Filter(alphanum; string)) <> Length(string) ) -Tom

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